What is the f(x)=(2x-3)/(\sqrt[3]{x+1)+3} ?

The f(x)=(2x-3)/(\sqrt[3]{x+1)+3} is

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f(x)=(2x-3)/(\sqrt[3]{x+1)+3}

Domain : x < - 28 or x > - 28

X Intercepts : (\frac{3}{2}, 0), Y Intercepts : (0, - \frac{3}{4})

Asymptotes : Vertical x = - 28

Extreme Points : Minimum (- 95.82578 \dots, 124.76771 \dots)

Interval Notation

Domain : (- \infty, - 28) \cup (- 28, \infty)

Solution steps

Domain of

Axis interception points of

X Intercepts

: (\frac{3}{2}, 0),

Y Intercepts

: (0, - \frac{3}{4})

Asymptotes of

Vertical

: x = - 28

Extreme Points of

Minimum

(- 95.82578 \dots, 124.76771 \dots)

y = 2 x^{2} + 3 x + 2

f (x) = - 3 (x - 5)^{2} + 3

f (x) = - 3 (x - 5)^{2} - 1

f (θ) = sin (2 θ) cos (θ) + sin^{2} (θ)

f (x) = - 4 x^{4} - 9 x^{3} + 2 x^{2} + 7 x - 2

What is the f(x)=(2x-3)/(\sqrt[3]{x+1)+3} ?
The f(x)=(2x-3)/(\sqrt[3]{x+1)+3} is