What is the y=(-2x^3+6x^2+8x-24)/(x^3+11x^2+38x+40) ?

The y=(-2x^3+6x^2+8x-24)/(x^3+11x^2+38x+40) is

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y=(-2x^3+6x^2+8x-24)/(x^3+11x^2+38x+40)

y = \frac{- 2 x ^{3} + 6 x ^{2} + 8 x - 24}{x ^{3} + 11 x ^{2} + 38 x + 40}

Domain : x < - 5 or - 5 < x < - 4 or - 4 < x < - 2 or x > - 2

Range : f (x) \leq 2 (97 - 563) or f (x) \geq 2 (563 + 97)

X Intercepts : (3, 0), (2, 0), Y Intercepts : (0, - \frac{3}{5})

Asymptotes : Vertical x = - 5, x = - 4, Horizontal y = - 2

Extreme Points : Minimum (- 1 - 23, 2 (97 + 563)), Maximum (- 1 + 23, 2 (97 - 563))

Interval Notation

Domain : (- \infty, - 5) \cup (- 5, - 4) \cup (- 4, - 2) \cup (- 2, \infty)

Range : (- \infty, 2 (97 - 563)] \cup [2 (563 + 97), \infty)

Solution steps

Domain of

\frac{- 2 x ^{3} + 6 x ^{2} + 8 x - 24}{x ^{3} + 11 x ^{2} + 38 x + 40} : x < - 5 or - 5 < x < - 4 or - 4 < x < - 2 or x > - 2

Range of

\frac{- 2 x ^{3} + 6 x ^{2} + 8 x - 24}{x ^{3} + 11 x ^{2} + 38 x + 40} : f (x) \leq 2 (97 - 563) or f (x) \geq 2 (563 + 97)

Axis interception points of

\frac{- 2 x ^{3} + 6 x ^{2} + 8 x - 24}{x ^{3} + 11 x ^{2} + 38 x + 40} :

X Intercepts

: (3, 0), (2, 0),

Y Intercepts

: (0, - \frac{3}{5})

Asymptotes of

\frac{- 2 x ^{3} + 6 x ^{2} + 8 x - 24}{x ^{3} + 11 x ^{2} + 38 x + 40} :

Vertical

: x = - 5, x = - 4,

Horizontal

: y = - 2

Extreme Points of

\frac{- 2 x ^{3} + 6 x ^{2} + 8 x - 24}{x ^{3} + 11 x ^{2} + 38 x + 40} :

Minimum

(- 1 - 23, 2 (97 + 563)),

Maximum

(- 1 + 23, 2 (97 - 563))

f (t) = \frac{2}{1 + 3 e ^{- 0.8 t}}

f (x) = x^{3} - 15 x^{2}

f (x) = - 2 x^{2} + 16 x - 33

f (x) = 7^{x - 3}

f (x) = 1 - 2 (x - 3)^{2}

What is the y=(-2x^3+6x^2+8x-24)/(x^3+11x^2+38x+40) ?
The y=(-2x^3+6x^2+8x-24)/(x^3+11x^2+38x+40) is