What is the slope ofintercept y-10=-2(x-3) ?

The slope ofintercept y-10=-2(x-3) is y=-2x+16

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slope ofintercept y-10=-2(x-3)

slope intercept

y - 10 = - 2 (x - 3)

y = - 2 x + 16

Solution steps

y - 10 = - 2 (x - 3)

Convert to slope intercept form:

y = - 2 x + 16

For a line in the form of

y = mx + b

, the slope is

m

and

y

intercept is

b

y = - 2 x + 16

- 36000 + 0.2 w

f (x) = cot^{2} (x)

(- 5.3) (2.7)

(- 2, 1), (3, - 1)

f (x) = 2^{x} - 3

What is the slope ofintercept y-10=-2(x-3) ?
The slope ofintercept y-10=-2(x-3) is y=-2x+16