What is the y=sqrt(2-x^2),0<= x<= sqrt(2) ?

The y=sqrt(2-x^2),0<= x<= sqrt(2) is

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y=sqrt(2-x^2),0<= x<= sqrt(2)

y = 2 - x^{2}, 0 \leq x \leq 2

Domain : 0 \leq x \leq 2

Range : 0 \leq f (x) \leq 2

X Intercepts : (2, 0), Y Intercepts : (0, 2)

Asymptotes : None

Extreme Points : Maximum (0, 2), Minimum (2, 0)

Interval Notation

Domain : [0, 2]

Range : [0, 2]

Solution steps

Domain of

2 - x^{2}, 0 \leq x \leq 2 : 0 \leq x \leq 2

Range of

2 - x^{2}, 0 \leq x \leq 2 : 0 \leq f (x) \leq 2

Axis interception points of

2 - x^{2}, 0 \leq x \leq 2 :

X Intercepts

: (2, 0),

Y Intercepts

: (0, 2)

Asymptotes of

2 - x^{2}, 0 \leq x \leq 2 :

None

Extreme Points of

2 - x^{2}, 0 \leq x \leq 2 :

Maximum

(0, 2),

Minimum

(2, 0)

f (y) = \frac{sin ( y )}{1 + cos ( y )}

f (x) = (\frac{2}{3})^{x} - 2

F (x) = x^{2} - 1

f (x) = \frac{1 - x}{x - 3}

f (a) = a^{6} + 6 a^{3} + 9

What is the y=sqrt(2-x^2),0<= x<= sqrt(2) ?
The y=sqrt(2-x^2),0<= x<= sqrt(2) is