What is the range of (2x^3+3)/(x^3-1) ?

The range of (2x^3+3)/(x^3-1) is f(x) 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of (2x^3+3)/(x^3-1)

range

\frac{2 x ^{3} + 3}{x ^{3} - 1}

f (x) < 2 or f (x) > 2

Interval Notation

(- \infty, 2) \cup (2, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{2 x ^{3} + 3}{x ^{3} - 1}

Inverse of

Find the domain of each inverse function

Domain of

Combine the intervals

f (x) < 2 or f (x) > 2

f (x) = ln (8 t)

f (x) = 4 x - 10, x \leq 2

\frac{x ^{3} + 3 x ^{2} + x + 3}{x + 1}

f (x) = x^{\frac{15}{7}} - x^{\frac{8}{7}}

f (x) = \frac{9 x - 1}{2 x + 8}

What is the range of (2x^3+3)/(x^3-1) ?
The range of (2x^3+3)/(x^3-1) is f(x)<2\lor f(x)>2