What is the domain of f(x)=(x^2(x+4))/((7x^2-3)) ?

The domain of f(x)=(x^2(x+4))/((7x^2-3)) is x sqrt(3/7)

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domain of f(x)=(x^2(x+4))/((7x^2-3))

domain

f (x) = \frac{x ^{2} ( x + 4 )}{( 7 x ^{2} - 3 )}

x < - \frac{3}{7} or - \frac{3}{7} < x < \frac{3}{7} or x > \frac{3}{7}

Interval Notation

(- \infty, - \frac{3}{7}) \cup (- \frac{3}{7}, \frac{3}{7}) \cup (\frac{3}{7}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{3}{7}, x = - \frac{3}{7}

The function domain

x < - \frac{3}{7} or - \frac{3}{7} < x < \frac{3}{7} or x > \frac{3}{7}

y = - 3 x^{2} + 30 x - 2

5 cos (π x - 2) + 5

f (x) = \frac{32}{x + 3}

y = cos (x - \frac{π}{6})

What is the domain of f(x)=(x^2(x+4))/((7x^2-3)) ?
The domain of f(x)=(x^2(x+4))/((7x^2-3)) is x<-sqrt(3/7)\lor-sqrt(3/7)<x<sqrt(3/7)\lor x>sqrt(3/7)