What is the f(x)=(x^5+12x^3-5x)/(2x^6+4x^3+x^2-2) ?

The f(x)=(x^5+12x^3-5x)/(2x^6+4x^3+x^2-2) is

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f(x)=(x^5+12x^3-5x)/(2x^6+4x^3+x^2-2)

f (x) = \frac{x ^{5} + 12 x ^{3} - 5 x}{2 x ^{6} + 4 x ^{3} + x ^{2} - 2}

Domain : x < - 1.27808 \dots or - 1.27808 \dots < x < 0.68933 \dots or x > 0.68933 \dots

Range : - 2996470380280.5303 < f (x) < 5.96189 E 15

X Intercepts : (0, 0), (- 6 + 41, 0), (- - 6 + 41, 0), Y Intercepts : (0, 0)

Asymptotes : Vertical x = - 1.27808 \dots, x = 0.68933 \dots, Horizontal y = 0

Extreme Points : Minimum (- 0.35304 \dots, - 0.60155 \dots), Maximum (0.46640 \dots, 0.80561 \dots)

Interval Notation

Domain : (- \infty, - 1.27808 \dots) \cup (- 1.27808 \dots, 0.68933 \dots) \cup (0.68933 \dots, \infty)

Range : (- 2996470380280.5303, 5.96189 E 15)

Solution steps

Domain of

\frac{x ^{5} + 12 x ^{3} - 5 x}{2 x ^{6} + 4 x ^{3} + x ^{2} - 2} : x < - 1.27808 \dots or - 1.27808 \dots < x < 0.68933 \dots or x > 0.68933 \dots

Range of

\frac{x ^{5} + 12 x ^{3} - 5 x}{2 x ^{6} + 4 x ^{3} + x ^{2} - 2} : - 2996470380280.5303 < f (x) < 5.96189 E 15

Axis interception points of

\frac{x ^{5} + 12 x ^{3} - 5 x}{2 x ^{6} + 4 x ^{3} + x ^{2} - 2} :

X Intercepts

: (0, 0), (- 6 + 41, 0), (- - 6 + 41, 0),

Y Intercepts

: (0, 0)

Asymptotes of

\frac{x ^{5} + 12 x ^{3} - 5 x}{2 x ^{6} + 4 x ^{3} + x ^{2} - 2} :

Vertical

: x = - 1.27808 \dots, x = 0.68933 \dots,

Horizontal

: y = 0

Extreme Points of

\frac{x ^{5} + 12 x ^{3} - 5 x}{2 x ^{6} + 4 x ^{3} + x ^{2} - 2} :

Minimum

(- 0.35304 \dots, - 0.60155 \dots),

Maximum

(0.46640 \dots, 0.80561 \dots)

y = - \frac{1}{2} x^{2} + 2 x + 2.5

y = (4 x^{2} - 16 x + 8)^{5}

f (x) = x - ∣ x ∣

f (x) = 4 x (x - 4) (x + 2)

x = sin (2 t)

What is the f(x)=(x^5+12x^3-5x)/(2x^6+4x^3+x^2-2) ?
The f(x)=(x^5+12x^3-5x)/(2x^6+4x^3+x^2-2) is