What is the y=(x^2)/(sqrt(1-x)),(-3, 9/2) ?

The y=(x^2)/(sqrt(1-x)),(-3, 9/2) is

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y=(x^2)/(sqrt(1-x)),(-3, 9/2)

y = \frac{x ^{2}}{1 - x}, (- 3, \frac{9}{2})

Domain : - 3 < x < 1

Range : f (x) \geq 0

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : Vertical x = 1

Extreme Points : Minimum (0, 0)

Interval Notation

Domain : (- 3, 1)

Range : [0, \infty)

Solution steps

Domain of

\frac{x ^{2}}{1 - x}, (- 3, \frac{9}{2}) : - 3 < x < 1

Range of

\frac{x ^{2}}{1 - x}, (- 3, \frac{9}{2}) : f (x) \geq 0

Axis interception points of

\frac{x ^{2}}{1 - x}, (- 3, \frac{9}{2}) :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

\frac{x ^{2}}{1 - x}, (- 3, \frac{9}{2}) :

Vertical

: x = 1

Extreme Points of

\frac{x ^{2}}{1 - x}, (- 3, \frac{9}{2}) :

Minimum

(0, 0)

y = \frac{1}{2} tan (x + \frac{π}{4})

f (x) = x - 5 x + 6

f (x) = \frac{2 x + 5}{4}

f (x) = \frac{2}{lo g _{10} ( x )}

f (x) = x^{- x}

What is the y=(x^2)/(sqrt(1-x)),(-3, 9/2) ?
The y=(x^2)/(sqrt(1-x)),(-3, 9/2) is