What is the domain of f(x)= 5/(sqrt(3+10x)) ?

The domain of f(x)= 5/(sqrt(3+10x)) is x>-3/10

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domain of f(x)= 5/(sqrt(3+10x))

domain

f (x) = \frac{5}{3 + 10 x}

x > - \frac{3}{10}

Interval Notation

(- \frac{3}{10}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{3}{10}

Find undefined (singularity) points:

x = - \frac{3}{10}

Combine real regions and undefined points for final function domain

x > - \frac{3}{10}

f (x) = ∣ x - 6 ∣

f (x) = \frac{2 x - 1}{3 x - 1}

t + 16

x + 2

f (x) = x^{2} + 3 x - 4

What is the domain of f(x)= 5/(sqrt(3+10x)) ?
The domain of f(x)= 5/(sqrt(3+10x)) is x>-3/10