What is the f(x)=(372)/(53+40cos(x)+9sin(x)) ?

The f(x)=(372)/(53+40cos(x)+9sin(x)) is

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f(x)=(372)/(53+40cos(x)+9sin(x))

f (x) = \frac{372}{53 + 40 cos ( x ) + 9 sin ( x )}

Period : 2 π

Domain : - \infty < x < \infty

Range : \frac{186}{47} \leq f (x) \leq 31

Y Intercepts : (0, 4)

Asymptotes : None

Extreme Points : Minimum (arctan (\frac{9}{40}) + 2 πn, \frac{186}{47}), Maximum (arctan (\frac{9}{40}) + π + 2 πn, 31)

Interval Notation

Domain : (- \infty, \infty)

Range : [\frac{186}{47}, 31]

Solution steps

Periodicity of

\frac{372}{53 + 40 cos ( x ) + 9 sin ( x )} : 2 π

Domain of

\frac{372}{53 + 40 cos ( x ) + 9 sin ( x )} : - \infty < x < \infty

Range of

\frac{372}{53 + 40 cos ( x ) + 9 sin ( x )} : \frac{186}{47} \leq f (x) \leq 31

Axis interception points of

\frac{372}{53 + 40 cos ( x ) + 9 sin ( x )} :

Y Intercepts

: (0, 4)

Asymptotes of

\frac{372}{53 + 40 cos ( x ) + 9 sin ( x )} :

None

Extreme Points of

\frac{372}{53 + 40 cos ( x ) + 9 sin ( x )} :

Minimum

(arctan (\frac{9}{40}) + 2 πn, \frac{186}{47}),

Maximum

(arctan (\frac{9}{40}) + π + 2 πn, 31)

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f (x) = 2 x^{3} - 6 x^{2} + 7 x + 1

f (x) = 4 sin (2 x - 3)

f (x) = 1 + x + 2

What is the f(x)=(372)/(53+40cos(x)+9sin(x)) ?
The f(x)=(372)/(53+40cos(x)+9sin(x)) is