What is the f(x)=6cos^2(x)-cos(x)-2,0<= x<= 2pi ?

The f(x)=6cos^2(x)-cos(x)-2,0<= x<= 2pi is

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f(x)=6cos^2(x)-cos(x)-2,0<= x<= 2pi

f (x) = 6 cos^{2} (x) - cos (x) - 2, 0 \leq x \leq 2 π

Period : 2 π

Domain : 0 \leq x \leq 2 π

Range : - \frac{49}{24} \leq f (x) \leq 5

X Intercepts : (arccos (\frac{2}{3}), 0), (2 π - arccos (\frac{2}{3}), 0), (\frac{2 π}{3}, 0), (\frac{4 π}{3}, 0), Y Intercepts : (0, 3)

Asymptotes : None

Extreme Points : Maximum (0, 3), Minimum (arccos (\frac{1}{12}), - \frac{49}{24}), Maximum (π, 5), Minimum (2 π - arccos (\frac{1}{12}), - \frac{49}{24}), Maximum (2 π, 3)

Interval Notation

Domain : [0, 2 π]

Range : [- \frac{49}{24}, 5]

Solution steps

Periodicity of

6 cos^{2} (x) - cos (x) - 2 : 2 π

Domain of

6 cos^{2} (x) - cos (x) - 2, 0 \leq x \leq 2 π : 0 \leq x \leq 2 π

Range of

6 cos^{2} (x) - cos (x) - 2, 0 \leq x \leq 2 π : - \frac{49}{24} \leq f (x) \leq 5

Axis interception points of

6 cos^{2} (x) - cos (x) - 2, 0 \leq x \leq 2 π :

X Intercepts

: (arccos (\frac{2}{3}), 0), (2 π - arccos (\frac{2}{3}), 0), (\frac{2 π}{3}, 0), (\frac{4 π}{3}, 0),

Y Intercepts

: (0, 3)

Asymptotes of

6 cos^{2} (x) - cos (x) - 2, 0 \leq x \leq 2 π :

None

Extreme Points of

6 cos^{2} (x) - cos (x) - 2, 0 \leq x \leq 2 π :

Maximum

(0, 3),

Minimum

(arccos (\frac{1}{12}), - \frac{49}{24}),

Maximum

(π, 5),

Minimum

(2 π - arccos (\frac{1}{12}), - \frac{49}{24}),

Maximum

(2 π, 3)

f (x) = ln (x^{2} + 25)

y = \frac{1}{7} sin (6 x)

f (x) = ln (x^{2} + 64)

f (x) = sin (x) \cdot x^{2}

f (a) = a^{4} + 1

What is the f(x)=6cos^2(x)-cos(x)-2,0<= x<= 2pi ?
The f(x)=6cos^2(x)-cos(x)-2,0<= x<= 2pi is