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Popular >

h(x)= x/(x^2+5)

Solution

h (x) = \frac{x}{x ^{2} + 5}

Solution

Domain : - \infty < x < \infty

Range : - \frac{1}{2 5} \leq f (x) \leq \frac{1}{2 5}

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : Horizontal y = 0

Extreme Points : Minimum (- 5, - \frac{1}{2 5}), Maximum (5, \frac{1}{2 5})

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [- \frac{1}{2 5}, \frac{1}{2 5}]

Solution steps

Domain of

\frac{x}{x ^{2} + 5} : - \infty < x < \infty

Range of

\frac{x}{x ^{2} + 5} : - \frac{1}{2 5} \leq f (x) \leq \frac{1}{2 5}

Axis interception points of

\frac{x}{x ^{2} + 5} :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

\frac{x}{x ^{2} + 5} :

Horizontal

: y = 0

Extreme Points of

\frac{x}{x ^{2} + 5} :

Minimum

(- 5, - \frac{1}{2 5}),

Maximum

(5, \frac{1}{2 5})

Popular Examples

y = - 3 x^{2} + 12 x - 4

f(x)=(5x)/(4+3x^2)

f (x) = \frac{5 x}{4 + 3 x ^{2}}

f(1/4)=4x^2+2x-2

f (\frac{1}{4}) = 4 x^{2} + 2 x - 2

f(x)=(1-e^x)/(ln(2-e^x))

f (x) = \frac{1 - e ^{x}}{ln ( 2 - e ^{x} )}

f(x)=(2x-5)/(3x+2)

f (x) = \frac{2 x - 5}{3 x + 2}

Frequently Asked Questions (FAQ)

What is the h(x)= x/(x^2+5) ?
The h(x)= x/(x^2+5) is