What is the y=(x^5)/6+1/(10x^3),1<= x<= 3 ?

The y=(x^5)/6+1/(10x^3),1<= x<= 3 is

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y=(x^5)/6+1/(10x^3),1<= x<= 3

y = \frac{x ^{5}}{6} + \frac{1}{10 x ^{3}}, 1 \leq x \leq 3

Domain : 1 \leq x \leq 3

Range : \frac{4}{15} \leq f (x) \leq \frac{5468}{135}

Intercepts : None

Asymptotes : None

Extreme Points : Minimum (1, \frac{4}{15}), Maximum (3, \frac{5468}{135})

Interval Notation

Domain : [1, 3]

Range : [\frac{4}{15}, \frac{5468}{135}]

Solution steps

Domain of

\frac{x ^{5}}{6} + \frac{1}{10 x ^{3}}, 1 \leq x \leq 3 : 1 \leq x \leq 3

Range of

\frac{x ^{5}}{6} + \frac{1}{10 x ^{3}}, 1 \leq x \leq 3 : \frac{4}{15} \leq f (x) \leq \frac{5468}{135}

Axis interception points of

\frac{x ^{5}}{6} + \frac{1}{10 x ^{3}}, 1 \leq x \leq 3 :

None

Asymptotes of

\frac{x ^{5}}{6} + \frac{1}{10 x ^{3}}, 1 \leq x \leq 3 :

None

Extreme Points of

\frac{x ^{5}}{6} + \frac{1}{10 x ^{3}}, 1 \leq x \leq 3 :

Minimum

(1, \frac{4}{15}),

Maximum

(3, \frac{5468}{135})

f (x) = (x - 1)^{2} \frac{3 x + 3}{x}

f (x) = - 2 - x^{2}

f (x) = (\frac{1}{2} x^{2} - 3 x) \cdot (\frac{2}{3} x^{3} + x)

y = 5 e^{- x^{2}}

f (x) = x^{3} - 5 x^{2} + 2 x - 3

What is the y=(x^5)/6+1/(10x^3),1<= x<= 3 ?
The y=(x^5)/6+1/(10x^3),1<= x<= 3 is