What is the f(x)={2x-1:-3<x<= 0,sqrt(x+1):0<x<= 8} ?

The f(x)={2x-1:-3<x<= 0,sqrt(x+1):0<x<= 8} is

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f(x)={2x-1:-3<x<= 0,sqrt(x+1):0<x<= 8}

f (x) = {2 x - 1 : - 3 < x \leq 0, x + 1 : 0 < x \leq 8}

Domain : - 3 < x \leq 8

Y Intercepts : (0, - 1)

Asymptotes : None

Monotone Intervals : Increasing : - 3 < x < 0, Increasing : 0 < x < 8

Interval Notation

Domain : (- 3, 8]

Solution steps

Domain of

{2 x - 1 : - 3 < x \leq 0, x + 1 : 0 < x \leq 8} : - 3 < x \leq 8

Axis interception points of

{2 x - 1 : - 3 < x \leq 0, x + 1 : 0 < x \leq 8} :

Y Intercepts

: (0, - 1)

Asymptotes of

{2 x - 1 : - 3 < x \leq 0, x + 1 : 0 < x \leq 8} :

None

Monotone Intervals of

{2 x - 1 : - 3 < x \leq 0, x + 1 : 0 < x \leq 8} :

Increasing

: - 3 < x < 0,

Increasing

: 0 < x < 8

f (x) = cos (6 x) - 3 sin (3 x) + 1

f (x) = x^{3} + 4 x^{2} + 2

f (x) = \frac{x ^{2} + 2 x}{1} + \frac{3 x - x ^{2}}{2 x}

y = 4 x^{2} + 24 x

What is the f(x)={2x-1:-3<x<= 0,sqrt(x+1):0<x<= 8} ?
The f(x)={2x-1:-3<x<= 0,sqrt(x+1):0<x<= 8} is