en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of x^2-6x+8

Solution

range

x^{2} - 6 x + 8

Solution

f (x) \geq - 1

+1

Interval Notation

[- 1, \infty)

Solution steps

Vertex of

x^{2} - 6 x + 8 :

Minimum

(3, - 1)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (3, - 1)

f (x) \geq - 1

Popular Examples

midpoint (17,-17),(0,-19)midpoint

(17, - 17), (0, - 19)

inverse of f(x)=(x+2)^2-4 inverse

f (x) = (x + 2)^{2} - 4

intercepts of f(x)=-16x^2+60x+2 intercepts

f (x) = - 16 x^{2} + 60 x + 2

domain of f(x)=x^5-3x+5 domain

f (x) = x^{5} - 3 x + 5

inverse of f(x)=6x(1-x)inverse

f (x) = 6 x (1 - x)

Frequently Asked Questions (FAQ)

What is the range of x^2-6x+8 ?
The range of x^2-6x+8 is f(x)>=-1