What is the f(y)=(-1)/(y(y-1))+(y^2)/(y-1) ?

The f(y)=(-1)/(y(y-1))+(y^2)/(y-1) is

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f(y)=(-1)/(y(y-1))+(y^2)/(y-1)

f (y) = \frac{- 1}{y ( y - 1 )} + \frac{y ^{2}}{y - 1}

Domain : y < 0 or 0 < y < 1 or y > 1

Range : f (y) \leq - 1 or f (y) > 3

Intercepts : None

Asymptotes : Vertical y = 0, Slant y = y + 1

Extreme Points : Maximum (- 1, - 1)

Interval Notation

Domain : (- \infty, 0) \cup (0, 1) \cup (1, \infty)

Range : (- \infty, - 1] \cup (3, \infty)

Solution steps

Domain of

\frac{- 1}{y ( y - 1 )} + \frac{y ^{2}}{y - 1} : y < 0 or 0 < y < 1 or y > 1

Range of

\frac{- 1}{y ( y - 1 )} + \frac{y ^{2}}{y - 1} : f (y) \leq - 1 or f (y) > 3

Axis interception points of

\frac{- 1}{y ( y - 1 )} + \frac{y ^{2}}{y - 1} :

None

Asymptotes of

\frac{- 1}{y ( y - 1 )} + \frac{y ^{2}}{y - 1} :

Vertical

: y = 0,

Slant

: y = y + 1

Extreme Points of

\frac{- 1}{y ( y - 1 )} + \frac{y ^{2}}{y - 1} :

Maximum

(- 1, - 1)

f (x) = ln (\frac{5 x - x ^{2}}{4})

f (x) = \frac{2 x ^{2} + 1}{3 x ^{3} + 1}

f (x) = 2 - x - (2 x + 5)

f (x) = 2 \cdot 4^{x}

What is the f(y)=(-1)/(y(y-1))+(y^2)/(y-1) ?
The f(y)=(-1)/(y(y-1))+(y^2)/(y-1) is