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Popular >

f(x)=(tan(x))/(1-tan^2(x))

Solution

f (x) = \frac{tan ( x )}{1 - tan ^{2} ( x )}

Solution

Period : \frac{π}{2}

Domain : \frac{π}{2} n < x < \frac{π}{4} + \frac{π}{2} n or \frac{π}{4} + \frac{π}{2} n < x < \frac{π}{2} + \frac{π}{2} n

Range : f (x) < 0 or f (x) > 0

X Intercepts : (\frac{πn}{2}, 0)

Asymptotes : Vertical x = \frac{π}{4} + \frac{π}{2} n

Extreme Points : None

+1

Interval Notation

Domain : (\frac{π}{2} n, \frac{π}{4} + \frac{π}{2} n) \cup (\frac{π}{4} + \frac{π}{2} n, \frac{π}{2} + \frac{π}{2} n)

Range : (- \infty, 0) \cup (0, \infty)

Solution steps

Periodicity of

\frac{tan ( x )}{1 - tan ^{2} ( x )} : \frac{π}{2}

Domain of

\frac{tan ( x )}{1 - tan ^{2} ( x )} : \frac{π}{2} n < x < \frac{π}{4} + \frac{π}{2} n or \frac{π}{4} + \frac{π}{2} n < x < \frac{π}{2} + \frac{π}{2} n

Range of

\frac{tan ( x )}{1 - tan ^{2} ( x )} : f (x) < 0 or f (x) > 0

Axis interception points of

\frac{tan ( x )}{1 - tan ^{2} ( x )} :

X Intercepts

: (\frac{πn}{2}, 0)

Asymptotes of

\frac{tan ( x )}{1 - tan ^{2} ( x )} :

Vertical

: x = \frac{π}{4} + \frac{π}{2} n

Extreme Points of

\frac{tan ( x )}{1 - tan ^{2} ( x )} :

None

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f (x) = - 2 x^{3} - 3

Frequently Asked Questions (FAQ)

What is the f(x)=(tan(x))/(1-tan^2(x)) ?
The f(x)=(tan(x))/(1-tan^2(x)) is