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Popular >

f(x)=(x^2-3x-4)/(x^2-9x+8)

Solution

f (x) = \frac{x ^{2} - 3 x - 4}{x ^{2} - 9 x + 8}

Solution

Domain : x < 1 or 1 < x < 8 or x > 8

Range : - \infty < f (x) < \infty

X Intercepts : (4, 0), (- 1, 0), Y Intercepts : (0, - \frac{1}{2})

Asymptotes : Vertical x = 1, x = 8, Horizontal y = 1

Extreme Points : None

+1

Interval Notation

Domain : (- \infty, 1) \cup (1, 8) \cup (8, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

\frac{x ^{2} - 3 x - 4}{x ^{2} - 9 x + 8} : x < 1 or 1 < x < 8 or x > 8

Range of

\frac{x ^{2} - 3 x - 4}{x ^{2} - 9 x + 8} : - \infty < f (x) < \infty

Axis interception points of

\frac{x ^{2} - 3 x - 4}{x ^{2} - 9 x + 8} :

X Intercepts

: (4, 0), (- 1, 0),

Y Intercepts

: (0, - \frac{1}{2})

Asymptotes of

\frac{x ^{2} - 3 x - 4}{x ^{2} - 9 x + 8} :

Vertical

: x = 1, x = 8,

Horizontal

: y = 1

Extreme Points of

\frac{x ^{2} - 3 x - 4}{x ^{2} - 9 x + 8} :

None

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Frequently Asked Questions (FAQ)

What is the f(x)=(x^2-3x-4)/(x^2-9x+8) ?
The f(x)=(x^2-3x-4)/(x^2-9x+8) is