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Popular >

f(x)=ln((x^2+1)/(x^2-1))

Solution

f (x) = ln (\frac{x ^{2} + 1}{x ^{2} - 1})

Solution

Domain : x < - 1 or x > 1

Range : f (x) > 0

Intercepts : None

Asymptotes : Vertical x = - 1, x = 1, Horizontal y = 0

Extreme Points : None

+1

Interval Notation

Domain : (- \infty, - 1) \cup (1, \infty)

Range : (0, \infty)

Solution steps

Domain of

ln (\frac{x ^{2} + 1}{x ^{2} - 1}) : x < - 1 or x > 1

Range of

ln (\frac{x ^{2} + 1}{x ^{2} - 1}) : f (x) > 0

Axis interception points of

ln (\frac{x ^{2} + 1}{x ^{2} - 1}) :

None

Asymptotes of

ln (\frac{x ^{2} + 1}{x ^{2} - 1}) :

Vertical

: x = - 1, x = 1,

Horizontal

: y = 0

Extreme Points of

ln (\frac{x ^{2} + 1}{x ^{2} - 1}) :

None

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Frequently Asked Questions (FAQ)

What is the f(x)=ln((x^2+1)/(x^2-1)) ?
The f(x)=ln((x^2+1)/(x^2-1)) is