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Popular >

f(t)=sqrt(t^2-9)

Solution

f (t) = t^{2} - 9

Solution

Domain : t \leq - 3 or t \geq 3

Range : f (t) \geq 0

X Intercepts : (3, 0), (- 3, 0)

Asymptotes : Slant y = t, y = - t

Extreme Points : Minimum (- 3, 0), Minimum (3, 0)

+1

Interval Notation

Domain : (- \infty, - 3] \cup [3, \infty)

Range : [0, \infty)

Solution steps

Domain of

t^{2} - 9 : t \leq - 3 or t \geq 3

Range of

t^{2} - 9 : f (t) \geq 0

Axis interception points of

t^{2} - 9 :

X Intercepts

: (3, 0), (- 3, 0)

Asymptotes of

t^{2} - 9 :

Slant

: y = t, y = - t

Extreme Points of

t^{2} - 9 :

Minimum

(- 3, 0),

Minimum

(3, 0)

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f (x) = 3 lo g_{2} (x + 1)

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f (x) = x^{4} - 4 x^{2} - 4

f (x) = \frac{x - 4}{4}

f (x) = 4 x^{2} + x - 8

f (x) = 4 x^{2} + x - 4

Frequently Asked Questions (FAQ)

What is the f(t)=sqrt(t^2-9) ?
The f(t)=sqrt(t^2-9) is