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Popular >

f(j)=cosh(0.942+j^{0.429})

Solution

f (j) = cosh (0.942 + j^{0.429})

Solution

Domain : j \geq 0

Y Intercepts : (0, \frac{e ^{\frac{471}{250}} + 1}{2 e ^{\frac{471}{500}}})

Asymptotes : None

Critical Points : j = 0

Inflection Points : None

+1

Interval Notation

Domain : [0, \infty)

Solution steps

Domain of

cosh (0.942 + j^{0.429}) : j \geq 0

Axis interception points of

cosh (0.942 + j^{0.429}) :

Y Intercepts

: (0, \frac{e ^{\frac{471}{250}} + 1}{2 e ^{\frac{471}{500}}})

Asymptotes of

cosh (0.942 + j^{0.429}) :

None

Critical Points of

cosh (0.942 + j^{0.429}) : j = 0

Inflection Points of

cosh (0.942 + j^{0.429}) :

None

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Frequently Asked Questions (FAQ)

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