What is the p(x)=(-300x)/((x^2+9)^{3/2)} ?

The p(x)=(-300x)/((x^2+9)^{3/2)} is

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p(x)=(-300x)/((x^2+9)^{3/2)}

p (x) = \frac{- 300 x}{( x ^{2} + 9 ) ^{\frac{3}{2}}}

Domain : - \infty < x < \infty

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : None

Extreme Points : Maximum (- \frac{3}{2}, \frac{200}{9 \cdot 3 ^{\frac{1}{2}}}), Minimum (\frac{3}{2}, - \frac{200}{9 \cdot 3 ^{\frac{1}{2}}})

Interval Notation

Domain : (- \infty, \infty)

Solution steps

Domain of

\frac{- 300 x}{( x ^{2} + 9 ) ^{\frac{3}{2}}} : - \infty < x < \infty

Axis interception points of

\frac{- 300 x}{( x ^{2} + 9 ) ^{\frac{3}{2}}} :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

\frac{- 300 x}{( x ^{2} + 9 ) ^{\frac{3}{2}}} :

None

Extreme Points of

\frac{- 300 x}{( x ^{2} + 9 ) ^{\frac{3}{2}}} :

Maximum

(- \frac{3}{2}, \frac{200}{9 \cdot 3 ^{\frac{1}{2}}}),

Minimum

(\frac{3}{2}, - \frac{200}{9 \cdot 3 ^{\frac{1}{2}}})

f (x) = - 2 x^{2} + 20 x - 43

f (x) = \frac{4}{3 x + 2}

f (x) = e^{2} ln (x)

f (x) = x^{2} - 7 x - 4

f (x) = \frac{x ^{4} - 3 x ^{3} - 11 x ^{2} + 23 x + 6}{x ^{2} - x - 6}