What is the f(x)=((x-5)(x-12))/((x+3)(x-2)(x-5)) ?

The f(x)=((x-5)(x-12))/((x+3)(x-2)(x-5)) is

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f(x)=((x-5)(x-12))/((x+3)(x-2)(x-5))

f (x) = \frac{( x - 5 ) ( x - 12 )}{( x + 3 ) ( x - 2 ) ( x - 5 )}

Domain : x < - 3 or - 3 < x < 2 or 2 < x < 5 or x > 5

Range : f (x) \leq \frac{5 - 2 6}{5} or f (x) \geq \frac{2 6 + 5}{5}

X Intercepts : (12, 0), Y Intercepts : (0, 2)

Asymptotes : Vertical x = - 3, x = 2, Horizontal y = 0

Extreme Points : Minimum (12 - 56, \frac{2 6 + 5}{5}), Maximum (12 + 56, \frac{5 - 2 6}{5})

Interval Notation

Domain : (- \infty, - 3) \cup (- 3, 2) \cup (2, 5) \cup (5, \infty)

Range : (- \infty, \frac{5 - 2 6}{5}] \cup [\frac{2 6 + 5}{5}, \infty)

Solution steps

Domain of

\frac{( x - 5 ) ( x - 12 )}{( x + 3 ) ( x - 2 ) ( x - 5 )} : x < - 3 or - 3 < x < 2 or 2 < x < 5 or x > 5

Range of

\frac{( x - 5 ) ( x - 12 )}{( x + 3 ) ( x - 2 ) ( x - 5 )} : f (x) \leq \frac{5 - 2 6}{5} or f (x) \geq \frac{2 6 + 5}{5}

Axis interception points of

\frac{( x - 5 ) ( x - 12 )}{( x + 3 ) ( x - 2 ) ( x - 5 )} :

X Intercepts

: (12, 0),

Y Intercepts

: (0, 2)

Asymptotes of

\frac{( x - 5 ) ( x - 12 )}{( x + 3 ) ( x - 2 ) ( x - 5 )} :

Vertical

: x = - 3, x = 2,

Horizontal

: y = 0

Extreme Points of

\frac{( x - 5 ) ( x - 12 )}{( x + 3 ) ( x - 2 ) ( x - 5 )} :

Minimum

(12 - 56, \frac{2 6 + 5}{5}),

Maximum

(12 + 56, \frac{5 - 2 6}{5})

f (x) = \frac{x - 1}{ln ( x - 2 )}

y = 6 x + 35

y = \frac{2 x + 3}{2 x ^{2} + x - 1}

f (x) = - \frac{1}{6} x^{2}

f (x) = 4 - 2 9 - x

What is the f(x)=((x-5)(x-12))/((x+3)(x-2)(x-5)) ?
The f(x)=((x-5)(x-12))/((x+3)(x-2)(x-5)) is