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Popular >

h(t)=-4.9t^2+10t+11

Solution

h (t) = - 4.9 t^{2} + 10 t + 11

Solution

Domain : - \infty < t < \infty

Range : f (t) \leq 16.10204 \dots

X Intercepts : (- \frac{- 50 + 7890}{49}, 0), (\frac{50 + 7890}{49}, 0), Y Intercepts : (0, 11)

Vertex : Maximum (1.02040 \dots, 16.10204 \dots)

Inverse : - \frac{- 100 + - 1960 t + 31560}{98}, - \frac{- 100 - - 1960 t + 31560}{98}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, 16.10204 \dots]

Solution steps

Domain of

- 4.9 t^{2} + 10 t + 11 : - \infty < t < \infty

Range of

- 4.9 t^{2} + 10 t + 11 : f (t) \leq 16.10204 \dots

Axis interception points of

- 4.9 t^{2} + 10 t + 11 :

X Intercepts

: (- \frac{- 50 + 7890}{49}, 0), (\frac{50 + 7890}{49}, 0),

Y Intercepts

: (0, 11)

Vertex of

- 4.9 t^{2} + 10 t + 11 :

Maximum

(1.02040 \dots, 16.10204 \dots)

Inverse of

- 4.9 t^{2} + 10 t + 11 : - \frac{- 100 + - 1960 t + 31560}{98}, - \frac{- 100 - - 1960 t + 31560}{98}

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Frequently Asked Questions (FAQ)

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