What is the periodicity of f(θ)=8cos(2θ)cos(4θ) ?

The periodicity of f(θ)=8cos(2θ)cos(4θ) is pi

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periodicity of f(θ)=8cos(2θ)cos(4θ)

periodicity

f (θ) = 8 cos (2 θ) cos (4 θ)

π

Solution steps

8 cos (2 θ) cos (4 θ)

is composed of the following functions and periods:

cos (2 θ)

with periodicity of

\frac{2 π}{2}

The compound periodicity is:

= π

\frac{( s - 4 )}{( s + 1 ) \cdot ( s + 2 )}, s > - 1

f (x) = e^{x} + 2 x - 4

f (x) = 4 - 2 x - x^{2}

f (x) = x + 3 - 3

What is the periodicity of f(θ)=8cos(2θ)cos(4θ) ?
The periodicity of f(θ)=8cos(2θ)cos(4θ) is pi