What is the inverse of f(x)=((x+1))/(2x+1) ?

The inverse of f(x)=((x+1))/(2x+1) is (1-x)/(2x-1)

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inverse of f(x)=((x+1))/(2x+1)

inverse

f (x) = \frac{( x + 1 )}{2 x + 1}

\frac{1 - x}{2 x - 1}

Solution steps

y = \frac{x + 1}{2 x + 1}

Replace

x

with

y

x = \frac{y + 1}{2 y + 1}

Solve for

y, x = \frac{y + 1}{2 y + 1}

\frac{1 - x}{2 x - 1}

f (x) = x - 11

f (x) = x^{6} (x - 2)^{5}

f (x) = 4 sec (\frac{x}{6} - 2 π) - 12

f (x) = - 2 x - 5

ln (x^{2} + 1)

What is the inverse of f(x)=((x+1))/(2x+1) ?
The inverse of f(x)=((x+1))/(2x+1) is (1-x)/(2x-1)