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Popular >

f(x)=((3x+4))/(x^2+7x+12)

Solution

f (x) = \frac{( 3 x + 4 )}{x ^{2} + 7 x + 12}

Solution

Domain : x < - 4 or - 4 < x < - 3 or x > - 3

Range : f (x) \leq - 410 + 13 or f (x) \geq 410 + 13

X Intercepts : (- \frac{4}{3}, 0), Y Intercepts : (0, \frac{1}{3})

Asymptotes : Vertical x = - 4, x = - 3, Horizontal y = 0

Extreme Points : Minimum (- \frac{2 ( 2 + 10 )}{3}, 13 + 410), Maximum (\frac{2 ( 10 - 2 )}{3}, 13 - 410)

+1

Interval Notation

Domain : (- \infty, - 4) \cup (- 4, - 3) \cup (- 3, \infty)

Range : (- \infty, - 410 + 13] \cup [410 + 13, \infty)

Solution steps

Domain of

\frac{3 x + 4}{x ^{2} + 7 x + 12} : x < - 4 or - 4 < x < - 3 or x > - 3

Range of

\frac{3 x + 4}{x ^{2} + 7 x + 12} : f (x) \leq - 410 + 13 or f (x) \geq 410 + 13

Axis interception points of

\frac{3 x + 4}{x ^{2} + 7 x + 12} :

X Intercepts

: (- \frac{4}{3}, 0),

Y Intercepts

: (0, \frac{1}{3})

Asymptotes of

\frac{3 x + 4}{x ^{2} + 7 x + 12} :

Vertical

: x = - 4, x = - 3,

Horizontal

: y = 0

Extreme Points of

\frac{3 x + 4}{x ^{2} + 7 x + 12} :

Minimum

(- \frac{2 ( 2 + 10 )}{3}, 13 + 410),

Maximum

(\frac{2 ( 10 - 2 )}{3}, 13 - 410)

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Frequently Asked Questions (FAQ)

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