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Popular >

f(θ)= 2/(1-sin(θ))

Solution

f (θ) = \frac{2}{1 - sin ( θ )}

Solution

Period : 2 π

Domain : 2 πn \leq θ < \frac{π}{2} + 2 πn or \frac{π}{2} + 2 πn < θ < 2 π + 2 πn

Range : f (θ) \geq 1

Y Intercepts : (0, 2)

Asymptotes : Vertical θ = \frac{π}{2} + 2 πn

Extreme Points : Minimum (\frac{3 π}{2} + 2 πn, 1)

+1

Interval Notation

Domain : [2 πn, \frac{π}{2} + 2 πn) \cup (\frac{π}{2} + 2 πn, 2 π + 2 πn)

Range : [1, \infty)

Solution steps

Periodicity of

\frac{2}{1 - sin ( θ )} : 2 π

Domain of

\frac{2}{1 - sin ( θ )} : 2 πn \leq θ < \frac{π}{2} + 2 πn or \frac{π}{2} + 2 πn < θ < 2 π + 2 πn

Range of

\frac{2}{1 - sin ( θ )} : f (θ) \geq 1

Axis interception points of

\frac{2}{1 - sin ( θ )} :

Y Intercepts

: (0, 2)

Asymptotes of

\frac{2}{1 - sin ( θ )} :

Vertical

: θ = \frac{π}{2} + 2 πn

Extreme Points of

\frac{2}{1 - sin ( θ )} :

Minimum

(\frac{3 π}{2} + 2 πn, 1)

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f(x)=x^2+1,-3<= x<= 3

f (x) = x^{2} + 1, - 3 \leq x \leq 3

y = 5 - 4 x - x^{3}

Frequently Asked Questions (FAQ)

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