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Popular >

midpoint (9,-8),(2,-5)

Solution

midpoint

(9, - 8), (2, - 5)

Solution

(\frac{11}{2}, - \frac{13}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (9, - 8), (x_{2}, y_{2}) = (2, - 5)

= (\frac{2 + 9}{2}, \frac{- 5 - 8}{2})

Refine

= (\frac{11}{2}, - \frac{13}{2})

Popular Examples

intercepts of y=-log_{2}(x+2)-3 intercepts

y = - lo g_{2} (x + 2) - 3

domain of f(x)=7+2/(3-x)domain

f (x) = 7 + \frac{2}{3 - x}

parity (x^2)/(x^2-1)parity

\frac{x ^{2}}{x ^{2} - 1}

asymptotes of f(x)=(2x)/(x^2-1)asymptotes

f (x) = \frac{2 x}{x ^{2} - 1}

range of f(x)= x/(x+3)range

f (x) = \frac{x}{x + 3}

Frequently Asked Questions (FAQ)

What is the midpoint (9,-8),(2,-5) ?
The midpoint (9,-8),(2,-5) is (11/2 ,-13/2)