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Popular >

f(x)=|x+1|-ln(x^2)

Solution

f (x) = ∣ x + 1 ∣ - ln (x^{2})

Solution

Domain : x < 0 or x > 0

Intercepts : None

Asymptotes : Vertical x = 0

Extreme Points : Minimum (- 2, - 2 ln (2) + 1), Minimum (2, - 2 ln (2) + 3)

+1

Interval Notation

Domain : (- \infty, 0) \cup (0, \infty)

Solution steps

Domain of

∣ x + 1 ∣ - ln (x^{2}) : x < 0 or x > 0

Axis interception points of

∣ x + 1 ∣ - ln (x^{2}) :

None

Asymptotes of

∣ x + 1 ∣ - ln (x^{2}) :

Vertical

: x = 0

Extreme Points of

∣ x + 1 ∣ - ln (x^{2}) :

Minimum

(- 2, - 2 ln (2) + 1),

Minimum

(2, - 2 ln (2) + 3)

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p (x) = x^{3} + 3 x^{2} - 4 x - 12

y = 4 lo g_{3} (x)

y = x^{2} + 38 x - 1

Frequently Asked Questions (FAQ)

What is the f(x)=|x+1|-ln(x^2) ?
The f(x)=|x+1|-ln(x^2) is