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Popular >

V(t)=2t^2-16t+40

Solution

V (t) = 2 t^{2} - 16 t + 40

Solution

Domain : - \infty < t < \infty

Range : f (t) \geq 8

Y Intercepts : (0, 40)

Vertex : Minimum (4, 8)

Inverse : \frac{16 + 8 t - 64}{4}, \frac{16 - 8 t - 64}{4}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [8, \infty)

Solution steps

Domain of

2 t^{2} - 16 t + 40 : - \infty < t < \infty

Range of

2 t^{2} - 16 t + 40 : f (t) \geq 8

Axis interception points of

2 t^{2} - 16 t + 40 :

Y Intercepts

: (0, 40)

Vertex of

2 t^{2} - 16 t + 40 :

Minimum

(4, 8)

Inverse of

2 t^{2} - 16 t + 40 : \frac{16 + 8 t - 64}{4}, \frac{16 - 8 t - 64}{4}

Popular Examples

f(x)=2-sqrt(9-x^2)

f (x) = 2 - 9 - x^{2}

f(x)=x^2-4x+7,2<= x<= 3

f (x) = x^{2} - 4 x + 7, 2 \leq x \leq 3

y=((x-2)(3-x))/(x^2)

y = \frac{( x - 2 ) ( 3 - x )}{x ^{2}}

y = - x^{2} + 3 x + 5

f(x)= 2/(2+x^2)

f (x) = \frac{2}{2 + x ^{2}}

Frequently Asked Questions (FAQ)

What is the V(t)=2t^2-16t+40 ?
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