What is the g(x)=3log_{10}((x-2)/5)+log_{10}(x^2+1) ?

The g(x)=3log_{10}((x-2)/5)+log_{10}(x^2+1) is

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g(x)=3log_{10}((x-2)/5)+log_{10}(x^2+1)

g (x) = 3 lo g_{10} (\frac{x - 2}{5}) + lo g_{10} (x^{2} + 1)

Domain : x > 2

X Intercepts : (3.95759 \dots, 0)

Asymptotes : Vertical x = 2

Extreme Points : None

Interval Notation

Domain : (2, \infty)

Solution steps

Domain of

3 lo g_{10} (\frac{x - 2}{5}) + lo g_{10} (x^{2} + 1) : x > 2

Axis interception points of

3 lo g_{10} (\frac{x - 2}{5}) + lo g_{10} (x^{2} + 1) :

X Intercepts

: (3.95759 \dots, 0)

Asymptotes of

3 lo g_{10} (\frac{x - 2}{5}) + lo g_{10} (x^{2} + 1) :

Vertical

: x = 2

Extreme Points of

3 lo g_{10} (\frac{x - 2}{5}) + lo g_{10} (x^{2} + 1) :

None

y = - \frac{5}{7} x - 1

f (x) = e^{x} (x^{2} - 1)

f (a) = \frac{49}{a}

y = x^{2} + 3 x - 6

What is the g(x)=3log_{10}((x-2)/5)+log_{10}(x^2+1) ?
The g(x)=3log_{10}((x-2)/5)+log_{10}(x^2+1) is