What is the f(x)=(x^4+2x^3-2)(x^3-3x^2+5) ?

The f(x)=(x^4+2x^3-2)(x^3-3x^2+5) is

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f(x)=(x^4+2x^3-2)(x^3-3x^2+5)

f (x) = (x^{4} + 2 x^{3} - 2) (x^{3} - 3 x^{2} + 5)

Domain : - \infty < x < \infty

Range : - \infty < f (x) < \infty

X Intercepts : (0.88503 \dots, 0), (- 2.19032 \dots, 0), (- 1.10380 \dots, 0), Y Intercepts : (0, - 10)

Asymptotes : None

Extreme Points : Maximum (- 1.86906 \dots, 34.28656 \dots), Minimum (0, - 10)

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

(x^{4} + 2 x^{3} - 2) (x^{3} - 3 x^{2} + 5) : - \infty < x < \infty

Range of

(x^{4} + 2 x^{3} - 2) (x^{3} - 3 x^{2} + 5) : - \infty < f (x) < \infty

Axis interception points of

(x^{4} + 2 x^{3} - 2) (x^{3} - 3 x^{2} + 5) :

X Intercepts

: (0.88503 \dots, 0), (- 2.19032 \dots, 0), (- 1.10380 \dots, 0),

Y Intercepts

: (0, - 10)

Asymptotes of

(x^{4} + 2 x^{3} - 2) (x^{3} - 3 x^{2} + 5) :

None

Extreme Points of

(x^{4} + 2 x^{3} - 2) (x^{3} - 3 x^{2} + 5) :

Maximum

(- 1.86906 \dots, 34.28656 \dots),

Minimum

(0, - 10)

f (x) = sin (4 x) sin (x)

f (t) = \frac{3}{8} + \frac{1}{8} cos (4 t) + \frac{1}{2} cos (2 t)

f (x) = 2 \cdot x - 3

p (x) = - 10 x^{2} + 1760 x - 50000

What is the f(x)=(x^4+2x^3-2)(x^3-3x^2+5) ?
The f(x)=(x^4+2x^3-2)(x^3-3x^2+5) is