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Popular >

p(x)=(x^2-3x)^2-2x^2+6x-8

Solution

p (x) = (x^{2} - 3 x)^{2} - 2 x^{2} + 6 x - 8

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq - 9

X Intercepts : (- 1, 0), (1, 0), (2, 0), (4, 0), Y Intercepts : (0, - 8)

Asymptotes : None

Extreme Points : Minimum (\frac{3 - 13}{2}, - 9), Maximum (\frac{3}{2}, \frac{25}{16}), Minimum (\frac{3 + 13}{2}, - 9)

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [- 9, \infty)

Solution steps

Domain of

(x^{2} - 3 x)^{2} - 2 x^{2} + 6 x - 8 : - \infty < x < \infty

Range of

(x^{2} - 3 x)^{2} - 2 x^{2} + 6 x - 8 : f (x) \geq - 9

Axis interception points of

(x^{2} - 3 x)^{2} - 2 x^{2} + 6 x - 8 :

X Intercepts

: (- 1, 0), (1, 0), (2, 0), (4, 0),

Y Intercepts

: (0, - 8)

Asymptotes of

(x^{2} - 3 x)^{2} - 2 x^{2} + 6 x - 8 :

None

Extreme Points of

(x^{2} - 3 x)^{2} - 2 x^{2} + 6 x - 8 :

Minimum

(\frac{3 - 13}{2}, - 9),

Maximum

(\frac{3}{2}, \frac{25}{16}),

Minimum

(\frac{3 + 13}{2}, - 9)

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g (x) = \frac{x}{x ^{2} + 36}

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f (18) = - \frac{2}{3} x + 3

Frequently Asked Questions (FAQ)

What is the p(x)=(x^2-3x)^2-2x^2+6x-8 ?
The p(x)=(x^2-3x)^2-2x^2+6x-8 is