What is the f(s)=(s^3+3s^2-s+1)/(4s^4-2s^3+s^2-s+2) ?

The f(s)=(s^3+3s^2-s+1)/(4s^4-2s^3+s^2-s+2) is

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f(s)=(s^3+3s^2-s+1)/(4s^4-2s^3+s^2-s+2)

f (s) = \frac{s ^{3} + 3 s ^{2} - s + 1}{4 s ^{4} - 2 s ^{3} + s ^{2} - s + 2}

Domain : - \infty < s < \infty

Range : - 0.01817 \dots \leq f (s) \leq 1.07457 \dots

X Intercepts : (- 3.38297 \dots, 0), Y Intercepts : (0, \frac{1}{2})

Asymptotes : Horizontal y = 0

Extreme Points : Minimum (- 6.82126 \dots, - 0.01817 \dots), Maximum (- 0.46138 \dots, 0.65590 \dots), Minimum (0.09299 \dots, 0.48776 \dots), Maximum (0.82674 \dots, 1.07457 \dots)

Interval Notation

Domain : (- \infty, \infty)

Range : [- 0.01817 \dots, 1.07457 \dots]

Solution steps

Domain of

\frac{s ^{3} + 3 s ^{2} - s + 1}{4 s ^{4} - 2 s ^{3} + s ^{2} - s + 2} : - \infty < s < \infty

Range of

\frac{s ^{3} + 3 s ^{2} - s + 1}{4 s ^{4} - 2 s ^{3} + s ^{2} - s + 2} : - 0.01817 \dots \leq f (s) \leq 1.07457 \dots

Axis interception points of

\frac{s ^{3} + 3 s ^{2} - s + 1}{4 s ^{4} - 2 s ^{3} + s ^{2} - s + 2} :

X Intercepts

: (- 3.38297 \dots, 0),

Y Intercepts

: (0, \frac{1}{2})

Asymptotes of

\frac{s ^{3} + 3 s ^{2} - s + 1}{4 s ^{4} - 2 s ^{3} + s ^{2} - s + 2} :

Horizontal

: y = 0

Extreme Points of

\frac{s ^{3} + 3 s ^{2} - s + 1}{4 s ^{4} - 2 s ^{3} + s ^{2} - s + 2} :

Minimum

(- 6.82126 \dots, - 0.01817 \dots),

Maximum

(- 0.46138 \dots, 0.65590 \dots),

Minimum

(0.09299 \dots, 0.48776 \dots),

Maximum

(0.82674 \dots, 1.07457 \dots)

f (x_{- 2}) = x_{- 2}

f (x) = e^{x} cos (x) d x

f (t) = sin (t) tan (t)

y = \frac{2}{x} + 1

f (x) = (x^{3})

What is the f(s)=(s^3+3s^2-s+1)/(4s^4-2s^3+s^2-s+2) ?
The f(s)=(s^3+3s^2-s+1)/(4s^4-2s^3+s^2-s+2) is