What is the y= 1/(7t^3)-(t^{-4})/5+2ln(3) ?

The y= 1/(7t^3)-(t^{-4})/5+2ln(3) is

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y= 1/(7t^3)-(t^{-4})/5+2ln(3)

y = \frac{1}{7 t ^{3}} - \frac{t ^{- 4}}{5} + 2 ln (3)

Domain : t < 0 or t > 0

X Intercepts : (0.49281 \dots, 0), (- 0.60054 \dots, 0)

Asymptotes : Horizontal y = 2 ln (3)

Extreme Points : Maximum (\frac{28}{15}, 2 ln (3) + \frac{3375}{614656})

Interval Notation

Domain : (- \infty, 0) \cup (0, \infty)

Solution steps

Domain of

\frac{1}{7 t ^{3}} - \frac{t ^{- 4}}{5} + 2 ln (3) : t < 0 or t > 0

Axis interception points of

\frac{1}{7 t ^{3}} - \frac{t ^{- 4}}{5} + 2 ln (3) :

X Intercepts

: (0.49281 \dots, 0), (- 0.60054 \dots, 0)

Asymptotes of

\frac{1}{7 t ^{3}} - \frac{t ^{- 4}}{5} + 2 ln (3) :

Horizontal

: y = 2 ln (3)

Extreme Points of

\frac{1}{7 t ^{3}} - \frac{t ^{- 4}}{5} + 2 ln (3) :

Maximum

(\frac{28}{15}, 2 ln (3) + \frac{3375}{614656})

f (x) = 3 x^{2} - 5 x^{(- 3)} + 6 x^{5}

f (x) = 6 x^{2} - 5 x - 7

y = sec^{2} (t) - tan^{2} (t)

f (x) = x^{5} - 3 x^{2} + 29

f (x) = x^{3} + 7 x^{2} - 5 x - 35

What is the y= 1/(7t^3)-(t^{-4})/5+2ln(3) ?
The y= 1/(7t^3)-(t^{-4})/5+2ln(3) is