What is the f(x)=arccos((x+c)/2)-pi/2 ?

The f(x)=arccos((x+c)/2)-pi/2 is Parity: Neither even nor odd Inverse: 2cos(x+pi/2)-c

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f(x)=arccos((x+c)/2)-pi/2

f (x) = arccos (\frac{x + c}{2}) - \frac{π}{2}

Parity : Neither even nor odd

Inverse : 2 cos (x + \frac{π}{2}) - c

Solution steps

Parity of

arccos (\frac{x + c}{2}) - \frac{π}{2} :

Neither even nor odd

Inverse of

arccos (\frac{x + c}{2}) - \frac{π}{2} : 2 cos (x + \frac{π}{2}) - c

g (x) = lo g_{0.25} (x)

f (x) = x^{3} + 8 x^{2} + x - 42

f (x) = \frac{x + 5}{x - 4}

f (x) = \frac{7 x - 5}{2}

f (x) = 12 x - 5

What is the f(x)=arccos((x+c)/2)-pi/2 ?
The f(x)=arccos((x+c)/2)-pi/2 is Parity: Neither even nor odd<br/>Inverse: 2cos(x+pi/2)-c