Solution
Solution
Solution steps
The parabola parameters are:
Simplify
Plug in to find the value
Therefore the parabola vertex is
If then the vertex is a maximum value
If then the vertex is a minimum value
Popular Examples
critical (x^3)/(x^2-1)range of f(x)=|x-2|intercepts of x^3-4x^2+8x-5extreme 6x^4+8x^3inverse of 1/(sqrt(x))
Frequently Asked Questions (FAQ)
What is the vertices y=x^2-6x+7 ?
The vertices y=x^2-6x+7 is Minimum (3,-2)