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Popular >

f(t)=5e-5t+2t^2-4

Solution

f (t) = 5 e - 5 t + 2 t^{2} - 4

Solution

Domain : - \infty < t < \infty

Range : f (t) \geq - \frac{57}{8} + 5 e

Y Intercepts : (0, 5 e - 4)

Vertex : Minimum (\frac{5}{4}, 5 e - \frac{57}{8})

Inverse : \frac{5 + 8 t + 57 - 40 e}{4}, \frac{5 - 8 t + 57 - 40 e}{4}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [- \frac{57}{8} + 5 e, \infty)

Solution steps

Domain of

5 e - 5 t + 2 t^{2} - 4 : - \infty < t < \infty

Range of

5 e - 5 t + 2 t^{2} - 4 : f (t) \geq - \frac{57}{8} + 5 e

Axis interception points of

5 e - 5 t + 2 t^{2} - 4 :

Y Intercepts

: (0, 5 e - 4)

Vertex of

5 e - 5 t + 2 t^{2} - 4 :

Minimum

(\frac{5}{4}, 5 e - \frac{57}{8})

Inverse of

5 e - 5 t + 2 t^{2} - 4 : \frac{5 + 8 t + 57 - 40 e}{4}, \frac{5 - 8 t + 57 - 40 e}{4}

Popular Examples

f(x)=x^4+8x^3+200

f (x) = x^{4} + 8 x^{3} + 200

y= 2/3 x^{3/2},0<= x<= 6

y = \frac{2}{3} x^{\frac{3}{2}}, 0 \leq x \leq 6

f (c) = 8 c

f(x)=3x-3+4-x^2-11-x-2

f (x) = 3 x - 3 + 4 - x^{2} - 11 - x - 2

f(x)=| 1/2 x^2-2x|

f (x) = \frac{1}{2} x^{2} - 2 x

Frequently Asked Questions (FAQ)

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