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Popular >

midpoint (8,-4),(12,2)

Solution

midpoint

(8, - 4), (12, 2)

Solution

(10, - 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (8, - 4), (x_{2}, y_{2}) = (12, 2)

= (\frac{12 + 8}{2}, \frac{2 - 4}{2})

Refine

= (10, - 1)

Popular Examples

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cos^{2} (x) + 2

slope of-17/13 slope

- \frac{17}{13}

intercepts of 2x^2+4x-1 intercepts

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domain of f(x)= 5/((x+2)(x-1))domain

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Frequently Asked Questions (FAQ)

What is the midpoint (8,-4),(12,2) ?
The midpoint (8,-4),(12,2) is (10,-1)