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Popular >

f(x)= 1/4 log_{3}(x^2-x-2)

Solution

f (x) = \frac{1}{4} lo g_{3} (x^{2} - x - 2)

Solution

Domain : x < - 1 or x > 2

Range : - \infty < f (x) < \infty

X Intercepts : (\frac{1 + 13}{2}, 0), (\frac{1 - 13}{2}, 0)

Asymptotes : Vertical x = - 1, x = 2

Extreme Points : None

+1

Interval Notation

Domain : (- \infty, - 1) \cup (2, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

\frac{1}{4} lo g_{3} (x^{2} - x - 2) : x < - 1 or x > 2

Range of

\frac{1}{4} lo g_{3} (x^{2} - x - 2) : - \infty < f (x) < \infty

Axis interception points of

\frac{1}{4} lo g_{3} (x^{2} - x - 2) :

X Intercepts

: (\frac{1 + 13}{2}, 0), (\frac{1 - 13}{2}, 0)

Asymptotes of

\frac{1}{4} lo g_{3} (x^{2} - x - 2) :

Vertical

: x = - 1, x = 2

Extreme Points of

\frac{1}{4} lo g_{3} (x^{2} - x - 2) :

None

Popular Examples

f(x)=-2x^4+17x^3-37x^2+7x+15

f (x) = - 2 x^{4} + 17 x^{3} - 37 x^{2} + 7 x + 15

parity f(x)=cos(ln(x))*tan(ln(x))parity

f (x) = cos (ln (x)) \cdot tan (ln (x))

f(x)=5x^2+10x+1

f (x) = 5 x^{2} + 10 x + 1

y = - 3 tan (\frac{1}{2} x)

f(x)=2x^4+2x^3+x^2-x-1

f (x) = 2 x^{4} + 2 x^{3} + x^{2} - x - 1

Frequently Asked Questions (FAQ)

What is the f(x)= 1/4 log_{3}(x^2-x-2) ?
The f(x)= 1/4 log_{3}(x^2-x-2) is