What is the f(x)=((x+2)(x+1)^2)/((x+2)(x-3)) ?

The f(x)=((x+2)(x+1)^2)/((x+2)(x-3)) is

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f(x)=((x+2)(x+1)^2)/((x+2)(x-3))

f (x) = \frac{( x + 2 ) ( x + 1 ) ^{2}}{( x + 2 ) ( x - 3 )}

Domain : x < - 2 or - 2 < x < 3 or x > 3

Range : f (x) \leq 0 or f (x) \geq 16

X Intercepts : (- 1, 0), Y Intercepts : (0, - \frac{1}{3})

Asymptotes : Vertical x = 3, Slant y = x + 5

Extreme Points : Maximum (- 1, 0), Minimum (7, 16)

Interval Notation

Domain : (- \infty, - 2) \cup (- 2, 3) \cup (3, \infty)

Range : (- \infty, 0] \cup [16, \infty)

Solution steps

Domain of

\frac{( x + 2 ) ( x + 1 ) ^{2}}{( x + 2 ) ( x - 3 )} : x < - 2 or - 2 < x < 3 or x > 3

Range of

\frac{( x + 2 ) ( x + 1 ) ^{2}}{( x + 2 ) ( x - 3 )} : f (x) \leq 0 or f (x) \geq 16

Axis interception points of

\frac{( x + 2 ) ( x + 1 ) ^{2}}{( x + 2 ) ( x - 3 )} :

X Intercepts

: (- 1, 0),

Y Intercepts

: (0, - \frac{1}{3})

Asymptotes of

\frac{( x + 2 ) ( x + 1 ) ^{2}}{( x + 2 ) ( x - 3 )} :

Vertical

: x = 3,

Slant

: y = x + 5

Extreme Points of

\frac{( x + 2 ) ( x + 1 ) ^{2}}{( x + 2 ) ( x - 3 )} :

Maximum

(- 1, 0),

Minimum

(7, 16)

f (x) = a (x + 3)^{2}

g (x) = 6 x

f (x) = - 2 x^{2} - 3 x + 20

P (x) = 2 x^{3} - 5 x^{2} - 23 x - 10

y = \frac{x ^{2}}{9 - x ^{2}}

What is the f(x)=((x+2)(x+1)^2)/((x+2)(x-3)) ?
The f(x)=((x+2)(x+1)^2)/((x+2)(x-3)) is