What is the f(x)=sqrt(9sin^2(x)+4cos^2(x)) ?

The f(x)=sqrt(9sin^2(x)+4cos^2(x)) is

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f(x)=sqrt(9sin^2(x)+4cos^2(x))

f (x) = 9 sin^{2} (x) + 4 cos^{2} (x)

Domain : True for all x \in R

Y Intercepts : (0, 2)

Asymptotes : None

Extreme Points : Minimum (πn, 9 sin^{2} (πn) + 4 cos^{2} (πn)), Maximum (\frac{π}{2} + πn, 9 sin^{2} (\frac{π}{2} + πn) + 4 cos^{2} (\frac{π}{2} + πn))

Interval Notation

Domain : (- \infty, \infty)

Solution steps

Domain of

9 sin^{2} (x) + 4 cos^{2} (x) :

True for all

x \in R

Axis interception points of

9 sin^{2} (x) + 4 cos^{2} (x) :

Y Intercepts

: (0, 2)

Asymptotes of

9 sin^{2} (x) + 4 cos^{2} (x) :

None

Extreme Points of

9 sin^{2} (x) + 4 cos^{2} (x) :

Minimum

(πn, 9 sin^{2} (πn) + 4 cos^{2} (πn)),

Maximum

(\frac{π}{2} + πn, 9 sin^{2} (\frac{π}{2} + πn) + 4 cos^{2} (\frac{π}{2} + πn))

f (j) = cosh (9 - j^{6})

f (x) = (\frac{x}{4 - x}) e^{- x}

y = ∣ x + 2 ∣ - 4

f (x) = \frac{1}{2} x - \frac{5}{3}

f (t) = t cosh (2 t)

What is the f(x)=sqrt(9sin^2(x)+4cos^2(x)) ?
The f(x)=sqrt(9sin^2(x)+4cos^2(x)) is