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Popular >

f(x)=(2x)/(x^2+5)

Solution

f (x) = \frac{2 x}{x ^{2} + 5}

Solution

Domain : - \infty < x < \infty

Range : - \frac{1}{5} \leq f (x) \leq \frac{1}{5}

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : Horizontal y = 0

Extreme Points : Minimum (- 5, - \frac{1}{5}), Maximum (5, \frac{1}{5})

+1

Solution steps

Domain of

\frac{2 x}{x ^{2} + 5} : - \infty < x < \infty

Range of

\frac{2 x}{x ^{2} + 5} : - \frac{1}{5} \leq f (x) \leq \frac{1}{5}

Axis interception points of

\frac{2 x}{x ^{2} + 5} :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

\frac{2 x}{x ^{2} + 5} :

Horizontal

: y = 0

Extreme Points of

\frac{2 x}{x ^{2} + 5} :

Minimum

(- 5, - \frac{1}{5}),

Maximum

(5, \frac{1}{5})

Popular Examples

f(x)=3x^3-2x^2+4

f (x) = 3 x^{3} - 2 x^{2} + 4

f(x)=3x^3-2x^2-1

f (x) = 3 x^{3} - 2 x^{2} - 1

f(x)=(2x-6)/(x-4)+1

f (x) = \frac{2 x - 6}{x - 4} + 1

y=-(x-1)^3(x+3)^2

y = - (x - 1)^{3} (x + 3)^{2}

f(x)=(2x^2-x-1)/(-2x+x^2-8)

f (x) = \frac{2 x ^{2} - x - 1}{- 2 x + x ^{2} - 8}

Frequently Asked Questions (FAQ)

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