What is the domain of f(x)=sqrt(4x+8) ?

The domain of f(x)=sqrt(4x+8) is x>=-2

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domain of f(x)=sqrt(4x+8)

domain

f (x) = 4 x + 8

x \geq - 2

Interval Notation

[- 2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

The function domain

x \geq - 2

f (x) = (x + 1)^{3} - 2

f (x) = 7 x - 3

2 x - 6 y = - 84

f (x) = (\frac{1}{4})^{x}

f (x) = \frac{- 5 x + 2}{x ^{2} + 10}