What is the f(x)=sqrt(3+x)+\sqrt[4]{7-x} ?

The f(x)=sqrt(3+x)+\sqrt[4]{7-x} is

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f(x)=sqrt(3+x)+\sqrt[4]{7-x}

f (x) = 3 + x + 4 7 - x

Domain : - 3 \leq x \leq 7

Range : 410 \leq f (x) \leq 4.02301 \dots

Y Intercepts : (0, 3 + 47)

Asymptotes : None

Extreme Points : Minimum (- 3, 410), Maximum (5.36471 \dots, 4.02301 \dots), Minimum (7, 10)

Interval Notation

Domain : [- 3, 7]

Range : [410, 4.02301 \dots]

Solution steps

Domain of

3 + x + 4 7 - x : - 3 \leq x \leq 7

Range of

3 + x + 4 7 - x : 410 \leq f (x) \leq 4.02301 \dots

Axis interception points of

3 + x + 4 7 - x :

Y Intercepts

: (0, 3 + 47)

Asymptotes of

3 + x + 4 7 - x :

None

Extreme Points of

3 + x + 4 7 - x :

Minimum

(- 3, 410),

Maximum

(5.36471 \dots, 4.02301 \dots),

Minimum

(7, 10)

f (a) = a - 4

f (a) = a - 8

y = \frac{1}{4 x ^{2} - 3 x + 9}

f (x) = x^{3} + \frac{3}{2} x^{2} - 6 x

\frac{x ^{10} + x ^{10} + x ^{10}}{x ^{10}}, x \neq = 0