What is the domain of f(x)=(16)/(x^2) ?

The domain of f(x)=(16)/(x^2) is x 0

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domain of f(x)=(16)/(x^2)

domain

f (x) = \frac{16}{x ^{2}}

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

x^{2} + 16 x + 64

6 - 8 x^{3}

(- 2, - 4), (2, 5)

f (x) = 2 ln (x - 1)

f (x) = \frac{10}{x + 7}

What is the domain of f(x)=(16)/(x^2) ?
The domain of f(x)=(16)/(x^2) is x<0\lor x>0