What is the domain of (sqrt(t-2))/(4t-24) ?

The domain of (sqrt(t-2))/(4t-24) is 2 6

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domain of (sqrt(t-2))/(4t-24)

domain

\frac{t - 2}{4 t - 24}

2 \leq t < 6 or t > 6

Interval Notation

[2, 6) \cup (6, \infty)

Solution steps

Find non-negative values for radicals:

t \geq 2

Find undefined (singularity) points:

t = 6

Combine real regions and undefined points for final function domain

2 \leq t < 6 or t > 6

(\frac{7}{x}) + 5

f (x) = \frac{5}{4} x + 15

\frac{x}{x - 1}

f (x) = \frac{5 - x}{x ^{2} - 9}

(5, - 6), (- 1, 2)

What is the domain of (sqrt(t-2))/(4t-24) ?
The domain of (sqrt(t-2))/(4t-24) is 2<= t<6\lor t>6