What is the y=((2x-2)(x+2))/((4x+4)(2x+1)) ?

The y=((2x-2)(x+2))/((4x+4)(2x+1)) is

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y=((2x-2)(x+2))/((4x+4)(2x+1))

y = \frac{( 2 x - 2 ) ( x + 2 )}{( 4 x + 4 ) ( 2 x + 1 )}

Domain : x < - 1 or - 1 < x < - \frac{1}{2} or x > - \frac{1}{2}

Range : f (x) \leq - 32 + \frac{9}{2} or f (x) \geq 32 + \frac{9}{2}

X Intercepts : (1, 0), (- 2, 0), Y Intercepts : (0, - 1)

Asymptotes : Vertical x = - 1, x = - \frac{1}{2}, Horizontal y = \frac{1}{4}

Extreme Points : Maximum (- 5 - 32, \frac{3 ( 3 - 2 2 )}{2}), Minimum (- 5 + 32, \frac{3 ( 3 + 2 2 )}{2})

Interval Notation

Domain : (- \infty, - 1) \cup (- 1, - \frac{1}{2}) \cup (- \frac{1}{2}, \infty)

Range : (- \infty, - 32 + \frac{9}{2}] \cup [32 + \frac{9}{2}, \infty)

Solution steps

Domain of

\frac{( 2 x - 2 ) ( x + 2 )}{( 4 x + 4 ) ( 2 x + 1 )} : x < - 1 or - 1 < x < - \frac{1}{2} or x > - \frac{1}{2}

Range of

\frac{( 2 x - 2 ) ( x + 2 )}{( 4 x + 4 ) ( 2 x + 1 )} : f (x) \leq - 32 + \frac{9}{2} or f (x) \geq 32 + \frac{9}{2}

Axis interception points of

\frac{( 2 x - 2 ) ( x + 2 )}{( 4 x + 4 ) ( 2 x + 1 )} :

X Intercepts

: (1, 0), (- 2, 0),

Y Intercepts

: (0, - 1)

Asymptotes of

\frac{( 2 x - 2 ) ( x + 2 )}{( 4 x + 4 ) ( 2 x + 1 )} :

Vertical

: x = - 1, x = - \frac{1}{2},

Horizontal

: y = \frac{1}{4}

Extreme Points of

\frac{( 2 x - 2 ) ( x + 2 )}{( 4 x + 4 ) ( 2 x + 1 )} :

Maximum

(- 5 - 32, \frac{3 ( 3 - 2 2 )}{2}),

Minimum

(- 5 + 32, \frac{3 ( 3 + 2 2 )}{2})

f (x) = x^{3} - 7 x^{2} + 10 x + 6

y = \frac{2}{3} x + \frac{7}{3}

y = - 2 x^{2} - 3 x - 1

f (x) = \frac{x + x}{x}

f (x) = - x^{2} + 12 x + 6

What is the y=((2x-2)(x+2))/((4x+4)(2x+1)) ?
The y=((2x-2)(x+2))/((4x+4)(2x+1)) is