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Popular >

f(x)=2(x+1)^2+5

Solution

f (x) = 2 (x + 1)^{2} + 5

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq 5

Y Intercepts : (0, 7)

Vertex : Minimum (- 1, 5)

Inverse : \frac{x - 5}{2} - 1, - \frac{x - 5}{2} - 1

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [5, \infty)

Solution steps

Domain of

2 (x + 1)^{2} + 5 : - \infty < x < \infty

Range of

2 (x + 1)^{2} + 5 : f (x) \geq 5

Axis interception points of

2 (x + 1)^{2} + 5 :

Y Intercepts

: (0, 7)

Vertex of

2 (x + 1)^{2} + 5 :

Minimum

(- 1, 5)

Inverse of

2 (x + 1)^{2} + 5 : \frac{x - 5}{2} - 1, - \frac{x - 5}{2} - 1

Popular Examples

f (x) = cot (3 x - 5)

f (x) = \frac{3}{1 + 3 x}

f (x) = 3 (4 x - 2) + 8

y = \frac{x + 1}{x + 3}

y = 6 x + 42

Frequently Asked Questions (FAQ)

What is the f(x)=2(x+1)^2+5 ?
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